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2x^2=3x-5=0
We move all terms to the left:
2x^2-(3x-5)=0
We get rid of parentheses
2x^2-3x+5=0
a = 2; b = -3; c = +5;
Δ = b2-4ac
Δ = -32-4·2·5
Δ = -31
Delta is less than zero, so there is no solution for the equation
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